10m=-3m^2

Solution for 10m=-3m^2 equation:

10m=-3m^2

We move all terms to the left:

10m-(-3m^2)=0

We get rid of parentheses

3m^2+10m=0

a = 3; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·3·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*3}=\frac{-20}{6}
=-3+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*3}=\frac{0}{6}
=0
$